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Texas Essential Knowledge and Skills (TEKS)
Surface Area & Volume
Grade:
8th Grade
Standard:
8.6.A
Description:
describe the volume formula
V
=
Bh
of a cylinder in terms of its base area and its height;
Standard:
8.6.B
Description:
model the relationship between the volume of a cylinder and a cone having both congruent bases and heights and connect that relationship to the formulas; and
Standard:
8.7.A
Description:
solve problems involving the volume of cylinders, cones, and spheres;
Standard:
8.7.B
Description:
use previous knowledge of surface area to make connections to the formulas for lateral and total surface area and determine solutions for problems involving rectangular prisms, triangular prisms, and cylinders;
Start Practicing!
8th Grade Math - Surface Area & Volume Lesson
1 of 3 -
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Volume Cone
=
1
3
π
r
2
h
Volume Sphere
=
4
3
π
r
3
Volume Cylinder
=
π
r
2
h
where
r
is the radius and
h
is the height
Example:
First, use the formula for the volume of a sphere to find the radius.
Volume
=
4
3
π
r
3
113.04
cm
3
=
4
3
π
r
3
113.04
cm
3
=
4
3
(
3.14
)
r
3
113.04
cm
3
÷
3.14
=
4
3
(
3.14
)
r
3
÷
3.14
36
cm
3
=
4
3
r
3
36
cm
3
×
3
4
=
4
3
r
3
×
3
4
27
cm
3
=
r
3
3
cm
=
r
The radius is 3 centimeters. So, the diameter is 6 centimeters.
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